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Question-29172




Question Number 29172 by byaw last updated on 04/Feb/18
Answered by mrW2 last updated on 04/Feb/18
mv_0 =(m+M)v_1   ⇒v_0 =(((m+M)v_1 )/m)=((0.084+20)/(0.084))×0.24=57.38 m/s
$${mv}_{\mathrm{0}} =\left({m}+{M}\right){v}_{\mathrm{1}} \\ $$$$\Rightarrow{v}_{\mathrm{0}} =\frac{\left({m}+{M}\right){v}_{\mathrm{1}} }{{m}}=\frac{\mathrm{0}.\mathrm{084}+\mathrm{20}}{\mathrm{0}.\mathrm{084}}×\mathrm{0}.\mathrm{24}=\mathrm{57}.\mathrm{38}\:{m}/{s} \\ $$

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