Question-29231

Question Number 29231 by Tinkutara last updated on 05/Feb/18

Answered by ajfour last updated on 05/Feb/18

e q . o f c h o r d o f c o n t a c t t o c i r c l e

x^{2} + y^{2} = 1 f r o m (x_{1}, y_{1}) i s

{x x}_{1} + {y y}_{1} = 1

g i v e n e q . o f c h o r d o f c o n t a c t i s

2 x + 2 y = 1

s o u p o n c o m p a r i s o n

A (x_{1}, y_{1}) \equiv (2, 2) .

Commented by Tinkutara last updated on 05/Feb/18

But how this equation is derived? Can this be solved without learning this formula?