Question-30856

Question Number 30856 by Joel578 last updated on 27/Feb/18

Commented by mrW2 last updated on 28/Feb/18

Q u e s t i o n i s w r o n g . I t s h o u l d b e :

\sin^{4} A = \dots

Answered by MJS last updated on 27/Feb/18

none of these

\frac{1}{2} \cos 2 A = \cos^{2} A - \frac{1}{2} = U

\frac{1}{8} \cos 4 A = \frac{1}{8} - \sin^{2} A \cos^{2} A = V

U + V = \cos^{4} A - \frac{3}{8}

U - V = \frac{3}{8} - \sin^{4} A

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