Question Number 30957 by Tinkutara last updated on 01/Mar/18
Answered by ajfour last updated on 01/Mar/18
$${mvr}=\frac{{nh}}{\mathrm{2}\pi} \\ $$$${T}=\frac{\mathrm{2}\pi{r}}{{v}}\:=\:\frac{\mathrm{2}\pi{r}}{\left(\frac{{nh}}{\mathrm{2}\pi{mr}}\right)}\:=\:\frac{\mathrm{4}\pi^{\mathrm{2}} {mr}^{\mathrm{2}} }{{nh}}\:. \\ $$
Commented by Tinkutara last updated on 01/Mar/18
Yes do you think options are wrong?
Commented by ajfour last updated on 01/Mar/18
$${yes}\:. \\ $$
Commented by Tinkutara last updated on 01/Mar/18
�� Thanks!