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Question-31018




Question Number 31018 by jasno91 last updated on 02/Mar/18
Commented by rahul 19 last updated on 02/Mar/18
sum of roots =− ((coefficient of b)/(coefficient of a))   let 3rd root= ζ  ⇒ (√3) +( −(√3) )+ζ = ((−1)/2).  hence ζ = −(1/2) .
$${sum}\:{of}\:{roots}\:=−\:\frac{{coefficient}\:{of}\:{b}}{{coefficient}\:{of}\:{a}} \\ $$$$\:{let}\:\mathrm{3}{rd}\:{root}=\:\zeta \\ $$$$\Rightarrow\:\sqrt{\mathrm{3}}\:+\left(\:−\sqrt{\mathrm{3}}\:\right)+\zeta\:=\:\frac{−\mathrm{1}}{\mathrm{2}}. \\ $$$${hence}\:\zeta\:=\:−\frac{\mathrm{1}}{\mathrm{2}}\:. \\ $$

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