Question Number 31406 by rahul 19 last updated on 08/Mar/18
Commented by mrW2 last updated on 08/Mar/18
$${OM}_{{r}} =\frac{{OA}_{{r}} +{OA}_{{r}+\mathrm{1}} }{\mathrm{2}}=\frac{\mathrm{1}+{q}}{\mathrm{2}}×{OA}_{{r}} \\ $$$$\Sigma{OM}_{{r}} =\frac{\mathrm{1}+{q}}{\mathrm{2}}×\Sigma{OA}_{{r}} =\frac{\mathrm{1}+{q}}{\mathrm{2}\left(\mathrm{1}−{q}\right)}×{OA}_{\mathrm{1}} \\ $$
Commented by rahul 19 last updated on 09/Mar/18
$${thank}\:{u}\:{sir}! \\ $$