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Question-31562




Question Number 31562 by mondodotto@gmail.com last updated on 10/Mar/18
Answered by Joel578 last updated on 10/Mar/18
∫ e^(ax)  + bx dx = 4e^(4x)  + (3/2)x^2    (1/a)e^(ax)  + (b/2)x^2  = 4e^(4x)  + (3/2)x^2   b = 3, a = ?
$$\int\:{e}^{{ax}} \:+\:{bx}\:{dx}\:=\:\mathrm{4}{e}^{\mathrm{4}{x}} \:+\:\frac{\mathrm{3}}{\mathrm{2}}{x}^{\mathrm{2}} \\ $$$$\:\frac{\mathrm{1}}{{a}}{e}^{{ax}} \:+\:\frac{{b}}{\mathrm{2}}{x}^{\mathrm{2}} \:=\:\mathrm{4}{e}^{\mathrm{4}{x}} \:+\:\frac{\mathrm{3}}{\mathrm{2}}{x}^{\mathrm{2}} \\ $$$${b}\:=\:\mathrm{3},\:{a}\:=\:? \\ $$

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