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Question-31949




Question Number 31949 by naka3546 last updated on 17/Mar/18
Answered by mrW2 last updated on 17/Mar/18
N=4n+2=2(2n+1)  M=16m+8=8(2m+1)  MN=16(2n+1)(2m+1)=16[2(m+n+2mn)+1]  =32(m+n+2mn)+16  ⇒y=16
$${N}=\mathrm{4}{n}+\mathrm{2}=\mathrm{2}\left(\mathrm{2}{n}+\mathrm{1}\right) \\ $$$${M}=\mathrm{16}{m}+\mathrm{8}=\mathrm{8}\left(\mathrm{2}{m}+\mathrm{1}\right) \\ $$$${MN}=\mathrm{16}\left(\mathrm{2}{n}+\mathrm{1}\right)\left(\mathrm{2}{m}+\mathrm{1}\right)=\mathrm{16}\left[\mathrm{2}\left({m}+{n}+\mathrm{2}{mn}\right)+\mathrm{1}\right] \\ $$$$=\mathrm{32}\left({m}+{n}+\mathrm{2}{mn}\right)+\mathrm{16} \\ $$$$\Rightarrow{y}=\mathrm{16} \\ $$

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