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Question-32236




Question Number 32236 by momo last updated on 22/Mar/18
Answered by ajfour last updated on 22/Mar/18
a=((Mgsin θ_S )/((7/5)MR^2 )) = ((mgsin θ_C )/((3/2)mR^2 ))  ⇒   ((sin θ_C )/(sin θ_S ))  =  ((15)/(14))  .
$${a}=\frac{{Mg}\mathrm{sin}\:\theta_{{S}} }{\frac{\mathrm{7}}{\mathrm{5}}{MR}^{\mathrm{2}} }\:=\:\frac{{mg}\mathrm{sin}\:\theta_{{C}} }{\frac{\mathrm{3}}{\mathrm{2}}{mR}^{\mathrm{2}} } \\ $$$$\Rightarrow\:\:\:\frac{\mathrm{sin}\:\theta_{{C}} }{\mathrm{sin}\:\theta_{{S}} }\:\:=\:\:\frac{\mathrm{15}}{\mathrm{14}}\:\:. \\ $$

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