Question Number 32308 by Ruchinna1 last updated on 22/Mar/18
Answered by Joel578 last updated on 23/Mar/18
$$\left(\mathrm{3}\right) \\ $$$${y}''''\:=\:\mathrm{5}{x} \\ $$$$\:{y}'''\:=\:\frac{\mathrm{5}}{\mathrm{2}}{x}^{\mathrm{2}} \:+\:{C} \\ $$$$\:\:{y}''\:=\:\frac{\mathrm{5}}{\mathrm{6}}{x}^{\mathrm{3}} \:+\:{C}_{\mathrm{1}} {x}\:+\:{C}_{\mathrm{2}} \\ $$$$\:\:\:{y}'\:=\:\frac{\mathrm{5}}{\mathrm{24}}{x}^{\mathrm{4}} \:+\:\frac{{C}_{\mathrm{1}} }{\mathrm{2}}{x}^{\mathrm{2}} \:+\:{C}_{\mathrm{2}} {x}\:+\:{C}_{\mathrm{3}} \\ $$$$\:\:\:\:{y}\:=\:\frac{\mathrm{1}}{\mathrm{24}}{x}^{\mathrm{5}} \:+\:\frac{\mathrm{1}}{\mathrm{6}}{C}_{\mathrm{1}} {x}^{\mathrm{3}} \:+\:\frac{\mathrm{1}}{\mathrm{2}}{C}_{\mathrm{2}} {x}^{\mathrm{2}} \:+\:{C}_{\mathrm{3}} {x}\:+\:{C}_{\mathrm{4}} \\ $$