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Question-32637

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Question Number 32637 by mondodotto@gmail.com last updated on 29/Mar/18
Answered by Joel578 last updated on 30/Mar/18
f(−1) = −2 f(0) = 2 Range: {x ∣ −2 ≤ x ≤ 2} f(0) = 2 f(2) = −6 Range: {x ∣ −6 ≤ x < 2} f(2) = −6 f(4) = −2 Range: {x ∣ −6 < x < −2}
f(−1)=−2f(0)=2Range:{x∣−2⩽x⩽2}f(0)=2f(2)=−6Range:{x∣−6⩽x<2}f(2)=−6f(4)=−2Range:{x∣−6<x<−2}
Commented by Joel578 last updated on 30/Mar/18

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