Question Number 32637 by mondodotto@gmail.com last updated on 29/Mar/18
Answered by Joel578 last updated on 30/Mar/18
$${f}\left(−\mathrm{1}\right)\:=\:−\mathrm{2} \\ $$$${f}\left(\mathrm{0}\right)\:=\:\mathrm{2} \\ $$$$\mathrm{Range}:\:\left\{{x}\:\mid\:−\mathrm{2}\:\leqslant\:{x}\:\leqslant\:\mathrm{2}\right\} \\ $$$$ \\ $$$${f}\left(\mathrm{0}\right)\:=\:\mathrm{2} \\ $$$${f}\left(\mathrm{2}\right)\:=\:−\mathrm{6} \\ $$$$\mathrm{Range}:\:\left\{{x}\:\mid\:−\mathrm{6}\:\leqslant\:{x}\:<\:\mathrm{2}\right\} \\ $$$$ \\ $$$${f}\left(\mathrm{2}\right)\:=\:−\mathrm{6} \\ $$$${f}\left(\mathrm{4}\right)\:=\:−\mathrm{2} \\ $$$$\mathrm{Range}:\:\left\{{x}\:\mid\:−\mathrm{6}\:<\:{x}\:<\:−\mathrm{2}\right\} \\ $$
Commented by Joel578 last updated on 30/Mar/18