Question-32891

Question Number 32891 by mondodotto@gmail.com last updated on 05/Apr/18

Commented by Tinkutara last updated on 05/Apr/18

It is wrong.

Commented by Joel578 last updated on 05/Apr/18

\sec x = \frac{1}{\cos x}

Commented by mrW2 last updated on 06/Apr/18

\sec^{- 1} x \neq {(\sec x)}^{- 1}

\sec^{- 1} x = a r c s e c x

{(s e c x)}^{- 1} = \frac{1}{\sec x} = \cos x

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