Question Number 33430 by rahul 19 last updated on 16/Apr/18
Commented by rahul 19 last updated on 16/Apr/18
$${Here}\:\boldsymbol{{E}}=\:{electric}\:{field}. \\ $$$$\boldsymbol{{V}}\:=\:{Electrostatic}\:{potential}\:. \\ $$
Commented by ajfour last updated on 16/Apr/18
$${E}_{{x}} =−\frac{\partial{V}}{\partial{x}}\: \\ $$$${hence}\:\:\:\left({B}\right)\:\:. \\ $$
Commented by rahul 19 last updated on 16/Apr/18
$${ohh},{yes}! \\ $$$${thank}\:{u}\:{sir}. \\ $$