Question Number 33800 by tawa tawa last updated on 25/Apr/18
Answered by ajfour last updated on 25/Apr/18
$${I}_{\mathrm{3}} ={I}_{{cell}} =\frac{\mathrm{6}{V}}{\left(\frac{\mathrm{5}×\mathrm{4}}{\mathrm{5}+\mathrm{4}}+\mathrm{3}+\mathrm{0}.\mathrm{5}\right)} \\ $$$$\:\:\:\:=\frac{\mathrm{6}}{\mathrm{5}.\mathrm{72}}\:\approx\:\mathrm{1}.\mathrm{05}{A} \\ $$$${I}_{\mathrm{5}} =\frac{\mathrm{4}}{\mathrm{9}}×\mathrm{1}.\mathrm{05}\:=\:\mathrm{0}.\mathrm{47}{A} \\ $$$${I}_{\mathrm{4}} =\mathrm{0}.\mathrm{58}{A} \\ $$$${V}_{\mathrm{3}} ={I}_{\mathrm{3}} ×\mathrm{3}\:=\mathrm{3}.\mathrm{15}{V} \\ $$$${V}_{\mathrm{4},\mathrm{5}} ={I}_{{cell}} ×\frac{\mathrm{20}}{\mathrm{9}}=\mathrm{1}.\mathrm{05}×\frac{\mathrm{20}}{\mathrm{9}}=\mathrm{2}.\mathrm{33}{V}\:\:. \\ $$
Commented by tawa tawa last updated on 25/Apr/18
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$
Commented by tawa tawa last updated on 25/Apr/18
$$\mathrm{please}\:\mathrm{sir}.\:\mathrm{why}\:\mathrm{is}\:\mathrm{it}\:\:\:\frac{\mathrm{4}}{\mathrm{9}}\:×\:\mathrm{1}.\mathrm{05}\:\:\:\mathrm{amd}\:\:\mathrm{please}\:\mathrm{how}\:\mathrm{is}\:\:\mathrm{I}_{\mathrm{4}} \:=\:\mathrm{0}.\mathrm{58}.\:\mathrm{thanks}\:\mathrm{sir}. \\ $$