Question-34617

Question Number 34617 by ajfour last updated on 09/May/18

Commented by candre last updated on 09/May/18

r_{t h} = R_{1} ∥ R_{3} + R_{2} ∥ R_{4}

V_{t h} = (\frac{R_{3}}{R_{1} + R_{3}} - \frac{R_{4}}{R_{2} + R_{4}}) ε

I = \frac{V_{t h}}{r_{t h}}

Commented by ajfour last updated on 09/May/18

F i n d c u r r e n t I .

Answered by ajfour last updated on 09/May/18

I = i_{1} - i_{3}

i = \frac{ε}{(\frac{R_{1} R_{2}}{R_{1} + R_{2}} + \frac{R_{3} R_{4}}{R_{3} + R_{4}})}

i_{1} = i (\frac{R_{2}}{R_{1} + R_{2}}); i_{3} = i (\frac{R_{4}}{R_{3} + R_{4}})

I = \frac{ε}{(\frac{R_{1} R_{2}}{R_{1} + R_{2}} + \frac{R_{3} R_{4}}{R_{3} + R_{4}})} [\frac{R_{2}}{R_{1} + R_{2}} - \frac{R_{4}}{R_{3} + R_{4}}]

I = \frac{ε (R_{2} R_{3} - R_{1} R_{4})}{R_{1} R_{2} (R_{3} + R_{4}) + R_{3} R_{4} (R_{1} + R_{2})} .

Answered by tanmay.chaudhury50@gmail.com last updated on 09/May/18

f o r b a l a n c e d w h e a s t o n b r i d g e t h a t m e a n s

w h e n \frac{R_{1}}{R_{2}} = \frac{R_{3}}{R_{4_{}}} I = 0