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Question-34639




Question Number 34639 by 255ketto last updated on 09/May/18
Answered by tanmay.chaudhury50@gmail.com last updated on 09/May/18
Commented by tanmay.chaudhury50@gmail.com last updated on 09/May/18
 the two curve meet at two points x<2 andx<4  two solution...x<2 and x<4
$$\:{the}\:{two}\:{curve}\:{meet}\:{at}\:{two}\:{points}\:{x}<\mathrm{2}\:{andx}<\mathrm{4} \\ $$$${two}\:{solution}…{x}<\mathrm{2}\:{and}\:{x}<\mathrm{4} \\ $$
Answered by MJS last updated on 09/May/18
25ln x=x^2   x_1 ≈1.044615  x_2 ≈6.966084  25log_(10)  x=x^2   x_1 ≈1.123220  x_2 ≈3.811472
$$\mathrm{25ln}\:{x}={x}^{\mathrm{2}} \\ $$$${x}_{\mathrm{1}} \approx\mathrm{1}.\mathrm{044615} \\ $$$${x}_{\mathrm{2}} \approx\mathrm{6}.\mathrm{966084} \\ $$$$\mathrm{25log}_{\mathrm{10}} \:{x}={x}^{\mathrm{2}} \\ $$$${x}_{\mathrm{1}} \approx\mathrm{1}.\mathrm{123220} \\ $$$${x}_{\mathrm{2}} \approx\mathrm{3}.\mathrm{811472} \\ $$

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