Question Number 34888 by arnabmaiti550@gmail.com last updated on 12/May/18
Commented by arnabmaiti550@gmail.com last updated on 12/May/18
$$\mathrm{please}\:\mathrm{help} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 13/May/18
$${Lorentz}\:{force}={q}\left(\boldsymbol{{V}}×\boldsymbol{{B}}\right) \\ $$$$={qVBsin}\mathrm{90}^{{o}} \\ $$$${qVB}\:\:\:{so}\:\:{mv}^{\mathrm{2}} /{R}={qvB} \\ $$$${mv}={qBR} \\ $$$${wR}={qBR}/{m} \\ $$$${w}=\frac{{qB}}{{m}} \\ $$$$\frac{\mathrm{2}\Pi}{{T}}=\frac{{qB}}{{m}} \\ $$$${T}=\frac{\mathrm{2}\Pi{m}}{{qB}\:} \\ $$$$ \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 13/May/18
