Question-34954

Question Number 34954 by ajfour last updated on 13/May/18

Commented by ajfour last updated on 13/May/18

F i n d r e s i s t a n c e o f a c y l i n d r i c a l

c o n d u c t o r o f r a d i u s b a n d t h i c k n e s s

t w i t h a c o n c e n t r i c h o l e o f r a d i u s

a, a c r o s s i t s i n n e r a n d o u t e r

s u r f a c e s . (c o n d u c t i v i t y g i v e n σ) .

Answered by tanmay.chaudhury50@gmail.com last updated on 13/May/18

d R = \frac{1}{σ} \times \frac{d l}{d A} l e t c o n s i d e r e l e m e n t a r y s h e l l

t h i c k n e s s d x, c r o s s a r e a 2 Π x \times t s o d l = d x

d A = 2 Π x t

= \frac{1}{σ} \times \frac{d x}{2 Π x t}

R = \frac{1}{2 Π σ t} \int_{a}^{b} \frac{d x}{x}

= \frac{1}{2 Π σ t} \times l n (\frac{b}{a})

Commented by ajfour last updated on 13/May/18

c o r r e c t a n s w e r .

b u t d A s h o u l d b e A a n d n o t d A .

Commented by tanmay.chaudhury50@gmail.com last updated on 14/May/18

t r u e \dots t h a n k s . .