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Question-35197




Question Number 35197 by Tinkutara last updated on 16/May/18
Answered by ajfour last updated on 17/May/18
  ⇒ P = ((3×320)/(290)) atm =((96)/(29))atm            =((96)/(30−1))=((96)/(30))(1+(1/(30)))             =3.2+((3.2)/(30)) = 3.31atm  ((n−△n)/3)=(n/(3.31))  ⇒  1−((△n)/n)=(3/(3.31))  or   ((△n)/n)=((0.31)/(3.31)) =((△V∣_(3.31atm) )/(V∣_(3.31atm) =10 l))  ⇒ (△V)_(1atm) =(△V)_(3.31atm) ×3.31                 =10×((0.31)/(3.31))×3.31                 =3.1 litres.
P=3×320290atm=9629atm=96301=9630(1+130)=3.2+3.230=3.31atmnn3=n3.311nn=33.31ornn=0.313.31=V3.31atmV3.31atm=10l(V)1atm=(V)3.31atm×3.31=10×0.313.31×3.31=3.1litres.
Commented by Tinkutara last updated on 16/May/18
Answer of (b) part is not correct Sir.
Commented by ajfour last updated on 17/May/18
what's the correct answer?
Commented by Tinkutara last updated on 17/May/18
Your answer is correct Sir. Thanks a lot!

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