Question-36059

Question Number 36059 by solihin last updated on 28/May/18

Answered by Rasheed.Sindhi last updated on 28/May/18

((z_1 +z_2 )/z_3 )=(((1+2i)+(4−3i))/(−5−2i)) =((5−i)/(−5−2i))×((−5+2i)/(−5+2i))=((−25+10i+5i+2)/((−5)^2 −(2i)^2 )) ((−23)/(29))+((15)/(29))i

$$\frac{\mathrm{z}_{\mathrm{1}} +\mathrm{z}_{\mathrm{2}} }{\mathrm{z}_{\mathrm{3}} }=\frac{\left(\mathrm{1}+\mathrm{2i}\right)+\left(\mathrm{4}−\mathrm{3i}\right)}{−\mathrm{5}−\mathrm{2i}} \\ $$$$=\frac{\mathrm{5}−\mathrm{i}}{−\mathrm{5}−\mathrm{2i}}×\frac{−\mathrm{5}+\mathrm{2i}}{−\mathrm{5}+\mathrm{2i}}=\frac{−\mathrm{25}+\mathrm{10i}+\mathrm{5i}+\mathrm{2}}{\left(−\mathrm{5}\right)^{\mathrm{2}} −\left(\mathrm{2i}\right)^{\mathrm{2}} } \\ $$$$\frac{−\mathrm{23}}{\mathrm{29}}+\frac{\mathrm{15}}{\mathrm{29}}\mathrm{i} \\ $$

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Question-36059

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