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Question-36346

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Question Number 36346 by behi83417@gmail.com last updated on 31/May/18
Commented by behi83417@gmail.com last updated on 31/May/18
find r in terms of :r_a ,r_b ,r_c
$${find}\:{r}\:{in}\:{terms}\:{of}\::{r}_{{a}} ,{r}_{{b}} ,{r}_{{c}} \\ $$
Commented by behi83417@gmail.com last updated on 31/May/18
To developer of tinku tara! if you can send a message to a member of forum,please send one to our grand master :mrW1 and say him to come back forum.this is the request of many of us.thanks.
$${To}\:{developer}\:{of}\:{tinku}\:{tara}! \\ $$$${if}\:{you}\:{can}\:{send}\:{a}\:{message}\:{to}\:{a}\: \\ $$$${member}\:{of}\:{forum},{please}\:{send}\:{one} \\ $$$${to}\:{our}\:{grand}\:{master}\::{mrW}\mathrm{1}\:{and}\:{say} \\ $$$${him}\:{to}\:{come}\:{back}\:{forum}.{this}\:{is}\:{the} \\ $$$${request}\:{of}\:{many}\:{of}\:{us}.{thanks}. \\ $$
Commented by MJS last updated on 01/Jun/18
this could be solved “backwards”: for a given triangle with sides a, b, c we know r=(d^((∗)) /(a+b+c)) and it′s possible to calculate r_a similar as I calculated another circle in question 35871 we get r_b and r_c by changing abc→bca→cab the only problem might be the inversion of the formulas... (∗) d=(√((a+b+c)(a+b−c)(a−b+c)(−a+b+c)))
$$\mathrm{this}\:\mathrm{could}\:\mathrm{be}\:\mathrm{solved}\:“\mathrm{backwards}'': \\ $$$$\mathrm{for}\:\mathrm{a}\:\mathrm{given}\:\mathrm{triangle}\:\mathrm{with}\:\mathrm{sides}\:{a},\:{b},\:{c}\:\mathrm{we}\:\mathrm{know} \\ $$$${r}=\frac{{d}^{\left(\ast\right)} }{{a}+{b}+{c}}\:\mathrm{and}\:\mathrm{it}'\mathrm{s}\:\mathrm{possible}\:\mathrm{to}\:\mathrm{calculate}\:{r}_{{a}} \:\mathrm{similar} \\ $$$$\mathrm{as}\:\mathrm{I}\:\mathrm{calculated}\:\mathrm{another}\:\mathrm{circle}\:\mathrm{in}\:\mathrm{question}\:\mathrm{35871} \\ $$$$\mathrm{we}\:\mathrm{get}\:{r}_{{b}} \:\mathrm{and}\:{r}_{{c}} \:\mathrm{by}\:\mathrm{changing}\:{abc}\rightarrow{bca}\rightarrow{cab} \\ $$$$\mathrm{the}\:\mathrm{only}\:\mathrm{problem}\:\mathrm{might}\:\mathrm{be}\:\mathrm{the}\:\mathrm{inversion}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{formulas}… \\ $$$$ \\ $$$$\left(\ast\right)\:{d}=\sqrt{\left({a}+{b}+{c}\right)\left({a}+{b}−{c}\right)\left({a}−{b}+{c}\right)\left(−{a}+{b}+{c}\right)} \\ $$
Commented by Tinku Tara last updated on 01/Jun/18
To behi As we dont take email id at the time of signup there is no way for us to approach any user via any other means.
$$\mathrm{To}\:\mathrm{behi} \\ $$$$ \\ $$$$\mathrm{As}\:\mathrm{we}\:\mathrm{dont}\:\mathrm{take}\:\mathrm{email}\:\mathrm{id}\:\mathrm{at}\:\mathrm{the} \\ $$$$\mathrm{time}\:\mathrm{of}\:\mathrm{signup}\:\mathrm{there}\:\mathrm{is}\:\mathrm{no}\:\mathrm{way}\:\mathrm{for} \\ $$$$\mathrm{us}\:\mathrm{to}\:\mathrm{approach}\:\mathrm{any}\:\mathrm{user}\:\mathrm{via} \\ $$$$\mathrm{any}\:\mathrm{other}\:\mathrm{means}. \\ $$
Commented by behi83417@gmail.com last updated on 01/Jun/18
thank you any way.
$${thank}\:{you}\:{any}\:{way}. \\ $$
Commented by MrW3 last updated on 11/Jun/18
nice question! thanks for your care!
$${nice}\:{question}! \\ $$$${thanks}\:{for}\:{your}\:{care}! \\ $$

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