Question-36548

Question Number 36548 by rahul 19 last updated on 03/Jun/18

Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18

Q=((kA(θ_2 −θ_1 )t)/l)=((i^2 Rt)/J)=(((V)^2 t)/(R J)) A=(40−2×0.1)^2 =1584.04cm^2 θ_2 −θ_1 =100 l=0.1cm V=100Volt J= R=(((V)^2 l)/(J kA(θ_2 −θ_1 )))

$${Q}=\frac{{kA}\left(\theta_{\mathrm{2}} −\theta_{\mathrm{1}} \right){t}}{{l}}=\frac{{i}^{\mathrm{2}} {Rt}}{{J}}=\frac{\left({V}\right)^{\mathrm{2}} {t}}{{R}\:{J}} \\ $$$${A}=\left(\mathrm{40}−\mathrm{2}×\mathrm{0}.\mathrm{1}\right)^{\mathrm{2}} =\mathrm{1584}.\mathrm{04}{cm}^{\mathrm{2}} \\ $$$$\theta_{\mathrm{2}} −\theta_{\mathrm{1}} =\mathrm{100} \\ $$$${l}=\mathrm{0}.\mathrm{1}{cm} \\ $$$${V}=\mathrm{100}{Volt} \\ $$$${J}= \\ $$$${R}=\frac{\left({V}\right)^{\mathrm{2}} {l}}{{J}\:{kA}\left(\theta_{\mathrm{2}} −\theta_{\mathrm{1}} \right)} \\ $$

Commented by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18