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Question-36548




Question Number 36548 by rahul 19 last updated on 03/Jun/18
Answered by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18
Q=((kA(θ_2 −θ_1 )t)/l)=((i^2 Rt)/J)=(((V)^2 t)/(R J))  A=(40−2×0.1)^2 =1584.04cm^2   θ_2 −θ_1 =100  l=0.1cm  V=100Volt  J=  R=(((V)^2 l)/(J kA(θ_2 −θ_1 )))
Q=kA(θ2θ1)tl=i2RtJ=(V)2tRJA=(402×0.1)2=1584.04cm2θ2θ1=100l=0.1cmV=100VoltJ=R=(V)2lJkA(θ2θ1)
Commented by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18
heat transfer ...attaching theorem...
heattransferattachingtheorem
Commented by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18
Commented by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18
Commented by tanmay.chaudhury50@gmail.com last updated on 03/Jun/18

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