Question-37058

Question Number 37058 by Tinkutara last updated on 08/Jun/18

Answered by ajfour last updated on 08/Jun/18

E_{c u b e} + E_{q} = 0

E_{c u b e} = - E_{q} = \frac{- q}{4 π ϵ_{0} d^{2}} .

Commented by Tinkutara last updated on 08/Jun/18

Sir can you please explain first line.

Commented by tanmay.chaudhury50@gmail.com last updated on 09/Jun/18

i t h i n k . . i n s i d e a c o n d u c t o r n e t e l e c t r i c f i e l d

i s z e r o . . s o E + E_{q} = 0 \dots e l e c t i c f i e l d a t t h e c e n t r e

o f c u b e d u e t o e x t e n a l c h a r g e i s E_{q} = \frac{1}{4 Π ϵ_{0}} \times \frac{q}{d^{2}}

E i s t h e v a l u e o f e l e c t r i c f i e l d a t t h e c e n t r e

o f c u b e d u e t o I N D U C E c h a r g e p r d u c e d f o r t h e

p r e s e n c e o f q \dots

Commented by Tinkutara last updated on 10/Jun/18

Thanks Sir!