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Question-37058




Question Number 37058 by Tinkutara last updated on 08/Jun/18
Answered by ajfour last updated on 08/Jun/18
E_(cube) +E_q =0  E_(cube) =−E_q =((−q)/(4πε_0 d^( 2) )) .
Ecube+Eq=0Ecube=Eq=q4πϵ0d2.
Commented by Tinkutara last updated on 08/Jun/18
Sir can you please explain first line.
Commented by tanmay.chaudhury50@gmail.com last updated on 09/Jun/18
i think..inside a conductor net electric field  is zero..so E+E_q =0...electic field at the centre  of cube due to extenal charge is E_q =(1/(4Πε_0 ))×(q/d^2 )  E is the value of electric field at the centre  of cube due to INDUCE charge prduced for the  presence of q...
ithink..insideaconductornetelectricfieldiszero..soE+Eq=0electicfieldatthecentreofcubeduetoextenalchargeisEq=14Πϵ0×qd2EisthevalueofelectricfieldatthecentreofcubeduetoINDUCEchargeprducedforthepresenceofq
Commented by Tinkutara last updated on 10/Jun/18
Thanks Sir!

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