Question Number 37058 by Tinkutara last updated on 08/Jun/18
![](https://www.tinkutara.com/question/4333.png)
Answered by ajfour last updated on 08/Jun/18
![E_(cube) +E_q =0 E_(cube) =−E_q =((−q)/(4πε_0 d^( 2) )) .](https://www.tinkutara.com/question/Q37062.png)
Commented by Tinkutara last updated on 08/Jun/18
Sir can you please explain first line.
Commented by tanmay.chaudhury50@gmail.com last updated on 09/Jun/18
![i think..inside a conductor net electric field is zero..so E+E_q =0...electic field at the centre of cube due to extenal charge is E_q =(1/(4Πε_0 ))×(q/d^2 ) E is the value of electric field at the centre of cube due to INDUCE charge prduced for the presence of q...](https://www.tinkutara.com/question/Q37126.png)
Commented by Tinkutara last updated on 10/Jun/18
Thanks Sir!