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Question-38939




Question Number 38939 by rahul 19 last updated on 01/Jul/18
Commented by rahul 19 last updated on 01/Jul/18
Pls solve this problem by Nodal Method.  Kirchhoff′s law is not allowed !
PlssolvethisproblembyNodalMethod.Kirchhoffslawisnotallowed!
Commented by rahul 19 last updated on 01/Jul/18
Answered by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18
Commented by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18
Commented by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18
pls check...
plscheck
Commented by rahul 19 last updated on 01/Jul/18
thank you sir ����
Commented by rahul 19 last updated on 01/Jul/18
pls check book sol. , is it correct ?
Commented by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18
book sol^n  is correct...i have found my mistake  and expressed...
booksolniscorrectihavefoundmymistakeandexpressed
Commented by tanmay.chaudhury50@gmail.com last updated on 01/Jul/18
2i_1 −5i_2 −1=0  2i_1 −5(((−1)/(13)))−1=0  I made mistake here in the  previous solution...pls check  2i_1 =1−(5/(13))=((8  )/(13))   so i_1 =(4/(13))  pd=2((4/(13))−((−1)/(13)))=((10)/(13))
2i15i21=02i15(113)1=0Imademistakehereintheprevioussolutionplscheck2i1=1513=813soi1=413pd=2(413113)=1013
Answered by ajfour last updated on 01/Jul/18
−2i_1 +2−1−i_1 =V_D −V_B =△V  ⇒     i_1 = ((1−△V)/3)           2i_2   = △V    ⇒   i_2  = ((△V)/2)  −1−i_3 −3i_3 +3 = △V   ⇒     i_3  = ((2−△V)/4)      As    i_2 =i_1 +i_3        ((△V)/2)=((1−△V)/3)+((2−△V)/4) =0      6△V=4−4△V+6−3△V     ⇒   △V = ((10)/(13)) .
2i1+21i1=VDVB=Vi1=1V32i2=Vi2=V21i33i3+3=Vi3=2V4Asi2=i1+i3V2=1V3+2V4=06V=44V+63VV=1013.
Commented by rahul 19 last updated on 01/Jul/18
Thank You sir ����

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