Menu Close

Question-39072

Tinku Tara 0 Comments
Pin




Question Number 39072 by ajfour last updated on 02/Jul/18
Commented by ajfour last updated on 02/Jul/18
Calculate x .
Calculatex.
Answered by MrW3 last updated on 02/Jul/18
(c/x)=((c+4.8)/(10)) ⇒10c=xc+4.8x ⇒c=((4.8x)/(10−x)) ((4.8)/x)=((4.8+c+x)/(10)) 48=x(4.8+c+x) 48=x(4.8+x+((4.8x)/(10−x))) 48(10−x)=x[(4.8+x)(10−x)+4.8x] 480−48x=x(48+10x−4.8x−x^2 +4.8x) 480−48x=48x+10x^2 −x^3 ⇒x^3 −10x^2 −96x+480=0 ⇒x=4.0
cx=c+4.810⇒10c=xc+4.8x⇒c=4.8x10−x4.8x=4.8+c+x1048=x(4.8+c+x)48=x(4.8+x+4.8x10−x)48(10−x)=x[(4.8+x)(10−x)+4.8x]480−48x=x(48+10x−4.8x−x2+4.8x)480−48x=48x+10x2−x3⇒x3−10x2−96x+480=0⇒x=4.0
Commented by MJS last updated on 02/Jul/18
there′s a mistake somewhere, MrW from (c/x)=((c+4.8)/(10)) and ((4.8)/x)=((4.8+c+x)/(10)) I get x^3 −10x^2 −96x+480=0 x_1 =3−(√(129)); c_1 =−9+(3/5)(√(129)) x_2 =3+(√(129)); c_2 =−9−(3/5)(√(129)) x_3 =4; c_3 =((16)/5)≈3.2
there′samistakesomewhere,MrWfromcx=c+4.810and4.8x=4.8+c+x10Igetx3−10x2−96x+480=0x1=3−129;c1=−9+35129x2=3+129;c2=−9−35129x3=4;c3=165≈3.2
Commented by MrW3 last updated on 02/Jul/18
Thank you both sirs. I have fixed the mistake.
Thankyoubothsirs.Ihavefixedthemistake.
Commented by MrW3 last updated on 02/Jul/18
Commented by ajfour last updated on 02/Jul/18
Thank you Sir MjS.
ThankyouSirMjS.
Answered by ajfour last updated on 02/Jul/18
((4.8)/x)=((4.8+c+x)/(10)) ....(i) ((10−x)/(4.8))=((10)/(4.8+c)) ...(ii) ⇒ 4.8+c = ((48)/(10−x)) So using this in (i) ((48)/x) = ((48)/(10−x))+x 480−48x=48x+x^2 (10−x) x^3 −10x^2 −96x+480=0 x= 4 .
4.8x=4.8+c+x10….(i)10−x4.8=104.8+c…(ii)⇒4.8+c=4810−xSousingthisin(i)48x=4810−x+x480−48x=48x+x2(10−x)x3−10x2−96x+480=0x=4.

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *