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Question-39457




Question Number 39457 by Raj Singh last updated on 06/Jul/18
Answered by MrW3 last updated on 06/Jul/18
y=f(x)=b e^(−(x/a))   f(0)=b  y′=f′(x)=−(b/a) e^(−(x/a))   f′(0)=−(b/a)  eqn. of line through (0,b) and with  slope m=−(b/a) is  y−b=−(b/a)(x−0)  ⇒ay+bx=ab
$${y}={f}\left({x}\right)={b}\:{e}^{−\frac{{x}}{{a}}} \\ $$$${f}\left(\mathrm{0}\right)={b} \\ $$$${y}'={f}'\left({x}\right)=−\frac{{b}}{{a}}\:{e}^{−\frac{{x}}{{a}}} \\ $$$${f}'\left(\mathrm{0}\right)=−\frac{{b}}{{a}} \\ $$$${eqn}.\:{of}\:{line}\:{through}\:\left(\mathrm{0},{b}\right)\:{and}\:{with} \\ $$$${slope}\:{m}=−\frac{{b}}{{a}}\:{is} \\ $$$${y}−{b}=−\frac{{b}}{{a}}\left({x}−\mathrm{0}\right) \\ $$$$\Rightarrow{ay}+{bx}={ab} \\ $$
Commented by Raj Singh last updated on 06/Jul/18
thanks sir
$${thanks}\:{sir} \\ $$

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