Question-40591

Question Number 40591 by mondodotto@gmail.com last updated on 24/Jul/18

Commented by mondodotto@gmail.com last updated on 24/Jul/18

roman (i) please

Answered by MJS last updated on 24/Jul/18

1 - 3 - 11 - 21 - 43 - 32 - 9

sum = 120

120 : 4 = 30 persons in each quartile

1 + 3 + 11 + 15 of 21 \Rightarrow q 1 \in [60 - 69]

6 of 21 + 24 of 43 \Rightarrow median \in [70 - 79]

19 of 43 + 11 of 32 \Rightarrow q 3 \in [80 - 89]

21 of 32 + 9

Commented by mondodotto@gmail.com last updated on 25/Jul/18

sir i stil dont undstnd this way

Commented by MJS last updated on 25/Jul/18

to find the borders of the quartiles you have

to make a sorted set of all the items and cut

this set in 4 parts of equal lenght . {there}^{'} s no

other way .

example :

the ages of 18 family members

{6, 9, 10, 22, 24, 25, 28, 38, 41, 45, 46, 48, 49, 67, 69, 74, 75, 86}

1^{st} half

{6, 9, 10, 22, 24, 25, 28, 38, 41}

2^{nd} half

{45, 46, 48, 49, 67, 69, 74, 75, 86}

m e d i a n = \frac{41 + 45}{2} = 43

1^{st} quarter

{6, 9, 10, 22, 24}

2^{nd} quarter

{24, 25, 28, 38, 41}

q 1 = 24

3^{rd} quarter

{45, 46, 48, 49, 67}

4^{th} quarter

{67, 69, 74, 75, 86}

q 3 = 67

{m i n, q 1, m e d, q 3, m a x} = {6, 24, 43, 67, 86}

Commented by mondodotto@gmail.com last updated on 25/Jul/18

thank you sir