Question Number 40813 by behi83417@gmail.com last updated on 27/Jul/18
Commented by MrW3 last updated on 28/Jul/18
$${x}={y}={z}=\mathrm{2} \\ $$
Commented by MrW3 last updated on 28/Jul/18
$$\Rightarrow{x}^{\mathrm{2}} +{y}^{\mathrm{2}} ={xyz} \\ $$$$\Rightarrow{y}^{\mathrm{2}} +{z}^{\mathrm{2}} ={xyz} \\ $$$$\Rightarrow{z}^{\mathrm{2}} +{x}^{\mathrm{2}} ={xyz} \\ $$$$\Rightarrow{x}^{\mathrm{2}} ={y}^{\mathrm{2}} ={z}^{\mathrm{2}} \\ $$$$\Rightarrow\mid{x}\mid=\mid{y}\mid=\mid{z}\mid \\ $$$$ \\ $$$${if}\:{x}=−{y}\:{then}\:{z}=\mathrm{0}\:{but}\:{z}\neq\mathrm{0} \\ $$$$\Rightarrow{x}={y}\:\Rightarrow{z}=\mathrm{2} \\ $$$${similarly} \\ $$$$\Rightarrow{y}={z}\:\Rightarrow{x}=\mathrm{2} \\ $$$$\Rightarrow{z}={x}\:\Rightarrow{y}=\mathrm{2} \\ $$$$ \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 28/Jul/18
$${excellent}… \\ $$
Commented by behi83417@gmail.com last updated on 28/Jul/18
$${thank}\:{you}\:{so}\:{much}\:{dear}\:{master}. \\ $$$${Q}#\mathrm{40457}\:{still}\:{waiting}\:{for}\:{your}\:{attintion} \\ $$$${sir}. \\ $$