Question-40975

Question Number 40975 by rahul 19 last updated on 30/Jul/18

Answered by ajfour last updated on 30/Jul/18

(b) 10 A / s

Commented by rahul 19 last updated on 31/Jul/18

Yes sir,

Answered by tanmay.chaudhury50@gmail.com last updated on 30/Jul/18

w h e n t = 0 L o f f e r i n f i n i t e r e s i s t a n c e s o n o c u r r e n t

t h r o u g h L \dots h e n c e (5 + 1 = 6 o h m), 6 o h m a n d

(2 + 4 = 6 o h m i n p a r a l l e l c o n n e c t i o n

\frac{1}{R} = \frac{1}{6} + \frac{1}{6} + \frac{1}{6} = \frac{3}{6} R = 2 o h m

c u r e d n t = \frac{6}{2} = 3 A

t h r o u g h A B \to B D 1 A c u r r e n t

t h t o u g h A \to D 1 A c u r r e n t

t h r o u g h A \to C \to D 1 A c u r r e n t \dots V_{A} - V_{B} = 1 \times 1

6 - V_{B} = 1 s o V_{B} = 5 V

V_{A} - V_{c} = 2 \times 1 = 2 V

6 - V_{c} = 2 V_{c} = 4 V

V_{B} = 5 V V_{c} . = 4 V

V_{B} - V_{c} = L \frac{d i}{d t}

\frac{d i}{d t} = \frac{V_{B} - V_{c}}{L} = \frac{5 - 4}{O . 1 H} = \frac{}{\frac{1}{10}} = 10

\frac{d i}{d t} = \frac{10 A] / s e c o n d \dots}{}

Commented by rahul 19 last updated on 31/Jul/18

thank you sir ��