Question Number 42106 by rahul 19 last updated on 18/Aug/18
Answered by tanmay.chaudhury50@gmail.com last updated on 18/Aug/18
$$\mathrm{5}{c}_{\mathrm{2}} ×\mathrm{2}!+\mathrm{5}{c}_{\mathrm{3}} ×\mathrm{3}!+\mathrm{5}{c}_{\mathrm{4}} ×\mathrm{4}!+\mathrm{5}{c}_{\mathrm{5}} ×\mathrm{5}! \\ $$$$=\mathrm{5}{p}_{\mathrm{2}} +\mathrm{5}{p}_{\mathrm{3}} +\mathrm{5}{p}_{\mathrm{4}} +\mathrm{5}{p}_{\mathrm{5}} \\ $$$$=\mathrm{20}+\mathrm{60}+\mathrm{120}+\mathrm{120}=\mathrm{320} \\ $$
Commented by rahul 19 last updated on 18/Aug/18
thanks sir ��