Question-43338

Question Number 43338 by ajfour last updated on 09/Sep/18

Commented by ajfour last updated on 10/Sep/18

F i n d r i n t e r m s o f R

(i n t h e c a s e o f c i r c l e s) .

Answered by ajfour last updated on 10/Sep/18

(R - r) \cos \frac{π}{6} = \frac{R}{2}

\Rightarrow r = R (1 - \frac{1}{\sqrt{3}}) .

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