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Question-43349




Question Number 43349 by peter frank last updated on 10/Sep/18
Answered by math1967 last updated on 10/Sep/18
(√(2+(√5)−(√(6−3(√5)+(√((3−(√(5)^2 ))))))))  (√(2+(√5)−(√(6−3(√5)+3−(√5)))))  (√(2+(√5)−(√(((√5)−2)^2 ))))  (√(2+(√5)−(√5)+2))  (√4)=2  (proved)
$$\sqrt{\mathrm{2}+\sqrt{\mathrm{5}}−\sqrt{\mathrm{6}−\mathrm{3}\sqrt{\mathrm{5}}+\sqrt{\left(\mathrm{3}−\sqrt{\left.\mathrm{5}\right)^{\mathrm{2}} }\right.}}} \\ $$$$\sqrt{\mathrm{2}+\sqrt{\mathrm{5}}−\sqrt{\mathrm{6}−\mathrm{3}\sqrt{\mathrm{5}}+\mathrm{3}−\sqrt{\mathrm{5}}}} \\ $$$$\sqrt{\mathrm{2}+\sqrt{\mathrm{5}}−\sqrt{\left(\sqrt{\mathrm{5}}−\mathrm{2}\right)^{\mathrm{2}} }} \\ $$$$\sqrt{\mathrm{2}+\sqrt{\mathrm{5}}−\sqrt{\mathrm{5}}+\mathrm{2}} \\ $$$$\sqrt{\mathrm{4}}=\mathrm{2}\:\:\left({proved}\right) \\ $$
Commented by peter frank last updated on 10/Sep/18
much respect
$${much}\:{respect} \\ $$
Answered by Joel578 last updated on 10/Sep/18
(√(14 − 6(√5))) = (√(14 − 2(√(45)))) = 3 − (√5)    (√(6 − 3(√5) + 3 − (√5))) = (√(9 − 4(√5))) = (√(9 − 2(√(20))))  = (√5) − 2    (√(2 + (√5) − (√5) + 2)) = (√4) = 2
$$\sqrt{\mathrm{14}\:−\:\mathrm{6}\sqrt{\mathrm{5}}}\:=\:\sqrt{\mathrm{14}\:−\:\mathrm{2}\sqrt{\mathrm{45}}}\:=\:\mathrm{3}\:−\:\sqrt{\mathrm{5}} \\ $$$$ \\ $$$$\sqrt{\mathrm{6}\:−\:\mathrm{3}\sqrt{\mathrm{5}}\:+\:\mathrm{3}\:−\:\sqrt{\mathrm{5}}}\:=\:\sqrt{\mathrm{9}\:−\:\mathrm{4}\sqrt{\mathrm{5}}}\:=\:\sqrt{\mathrm{9}\:−\:\mathrm{2}\sqrt{\mathrm{20}}} \\ $$$$=\:\sqrt{\mathrm{5}}\:−\:\mathrm{2} \\ $$$$ \\ $$$$\sqrt{\mathrm{2}\:+\:\sqrt{\mathrm{5}}\:−\:\sqrt{\mathrm{5}}\:+\:\mathrm{2}}\:=\:\sqrt{\mathrm{4}}\:=\:\mathrm{2} \\ $$
Commented by malwaan last updated on 10/Sep/18
3−(√5) ??
$$\mathrm{3}−\sqrt{\mathrm{5}}\:?? \\ $$
Commented by Joel578 last updated on 10/Sep/18
(3 − (√5))^2  = 9 − 6(√5) + 5 = 14 − 6(√5) = 14 − 2(√(45))  (√((3 − (√5))^2 )) = (√(14 − 2(√(45))))
$$\left(\mathrm{3}\:−\:\sqrt{\mathrm{5}}\right)^{\mathrm{2}} \:=\:\mathrm{9}\:−\:\mathrm{6}\sqrt{\mathrm{5}}\:+\:\mathrm{5}\:=\:\mathrm{14}\:−\:\mathrm{6}\sqrt{\mathrm{5}}\:=\:\mathrm{14}\:−\:\mathrm{2}\sqrt{\mathrm{45}} \\ $$$$\sqrt{\left(\mathrm{3}\:−\:\sqrt{\mathrm{5}}\right)^{\mathrm{2}} }\:=\:\sqrt{\mathrm{14}\:−\:\mathrm{2}\sqrt{\mathrm{45}}} \\ $$
Commented by peter frank last updated on 10/Sep/18
    thanks
$$ \\ $$$$ \\ $$$${thanks} \\ $$

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