Question Number 44035 by rahul 19 last updated on 20/Sep/18
Commented by tanmay.chaudhury50@gmail.com last updated on 20/Sep/18
$$\left(\overset{\rightarrow} {{x}}.\overset{\rightarrow} {{z}}\right)\overset{\rightarrow} {{y}}−\left(\overset{\rightarrow} {{x}}.\overset{\rightarrow} {{y}}\right)\overset{\rightarrow} {{z}}=\overset{\rightarrow} {{a}} \\ $$$$\left(\sqrt{\mathrm{2}}\:×\sqrt{\mathrm{2}}\:{cos}\mathrm{60}^{{o}} \right)\overset{\rightarrow} {{y}}−\left(\sqrt{\mathrm{2}}\:×\sqrt{\mathrm{2}}\:{cos}\mathrm{60}^{{o}} \right)\overset{\rightarrow} {{z}}=\overset{\rightarrow} {{a}} \\ $$$$\overset{\rightarrow} {{y}}−\overset{\rightarrow} {{z}}=\overset{\rightarrow} {{a}} \\ $$$$\overset{\rightarrow} {{z}}−\overset{\rightarrow} {{x}}=\overset{\rightarrow} {{b}} \\ $$$$\overset{\rightarrow} {{x}}×\overset{\rightarrow} {{y}}=\overset{\rightarrow} {{c}} \\ $$$$\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}=\left(\overset{\rightarrow} {{y}}−\overset{\rightarrow} {{x}}\right)×\left(\overset{\rightarrow} {{x}}×\overset{\rightarrow} {{y}}\right) \\ $$$$=\overset{\rightarrow} {{y}}×\left(\overset{\rightarrow} {{x}}×\overset{\rightarrow} {{y}}\right)−\overset{\rightarrow} {{x}}×\left(\overset{\rightarrow} {{x}}×\overset{\rightarrow} {{y}}\right) \\ $$$$=\left(\overset{\rightarrow} {{y}}.\overset{\rightarrow} {{y}}\right)\overset{\rightarrow} {{x}}−\left(\overset{\rightarrow} {{y}}.\overset{\rightarrow} {{x}}\right)\overset{\rightarrow} {{y}}−\left(\overset{\rightarrow} {{x}}.\overset{\rightarrow} {{y}}\right)\overset{\rightarrow} {{x}}+\left(\overset{\rightarrow} {{x}}.\overset{\rightarrow} {{x}}\right)\overset{\rightarrow} {{y}} \\ $$$$=\mathrm{2}\overset{\rightarrow} {{x}}−\overset{\rightarrow} {{y}}−\overset{\rightarrow} {{x}}+\mathrm{2}\overset{\rightarrow} {{y}} \\ $$$$=\overset{\rightarrow} {{x}}+\overset{\rightarrow} {{y}} \\ $$$$\overset{\rightarrow} {{x}}+\overset{\rightarrow} {{y}}=\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}} \\ $$$$\overset{\rightarrow} {{y}}−\overset{\rightarrow} {{x}}=\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}} \\ $$$$\mathrm{2}\overset{\rightarrow} {{x}}=\left[\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}−\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)\right] \\ $$$$\overset{\rightarrow} {{x}}=\frac{\mathrm{1}}{\mathrm{2}}\left[\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}−\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)\right] \\ $$$$\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}+\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)=\overset{\rightarrow} {{x}}+\overset{\rightarrow} {{y}}+\overset{\rightarrow} {{y}}−\overset{\rightarrow} {{x}} \\ $$$$\overset{\rightarrow} {{y}}=\frac{\mathrm{1}}{\mathrm{2}}\left[\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}+\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)\right] \\ $$$$\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}+\overset{\rightarrow} {{b}}−\overset{\rightarrow} {{a}} \\ $$$$=\overset{\rightarrow} {{x}}+\overset{\rightarrow} {{y}}+\overset{\rightarrow} {{z}}−\overset{\rightarrow} {{x}}−\left(\overset{\rightarrow} {{y}}−\overset{\rightarrow} {{z}}\right) \\ $$$$=\overset{\rightarrow} {{x}}+\overset{\rightarrow} {{y}}+\overset{\rightarrow} {{z}}−\overset{\rightarrow} {{x}}−\overset{\rightarrow} {{y}}+\overset{\rightarrow} {{z}} \\ $$$$=\mathrm{2}\overset{\rightarrow} {{z}} \\ $$$$\overset{\rightarrow} {{z}}=\frac{\mathrm{1}}{\mathrm{2}}\left[\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right)×\overset{\rightarrow} {{c}}+\overset{\rightarrow} {{b}}−\overset{\rightarrow} {{a}}\right) \\ $$
Commented by rahul 19 last updated on 21/Sep/18
Thank you Sir !
Commented by Micky24 last updated on 09/Dec/18
$${pls}\:{how} \\ $$