Question Number 44805 by jasno91 last updated on 05/Oct/18
Answered by Kunal12588 last updated on 05/Oct/18
$${let}\:{the}\:{numbers}\:{be}\:{a},{b},{c} \\ $$$${a}:{b}:{c}=\mathrm{4}:\mathrm{5}:\mathrm{6} \\ $$$${let}\:{a}=\mathrm{4}{x},\:{b}=\mathrm{5}{x},\:{c}=\mathrm{6}{x} \\ $$$${here}\:\mathrm{6}{x}>\mathrm{5}{x}>\mathrm{4}{x} \\ $$$$\therefore\:\mathrm{6}{x}+\mathrm{4}{x}=\mathrm{5}{x}+\mathrm{55} \\ $$$$\Rightarrow{x}=\mathrm{11} \\ $$$${numbers}\:{are}\:\mathrm{44},\mathrm{55},\mathrm{66}. \\ $$