Question Number 44807 by jasno91 last updated on 05/Oct/18
Answered by Kunal12588 last updated on 05/Oct/18
$$\left({a}+{b}\right)^{\mathrm{2}} ={a}^{\mathrm{2}} +\mathrm{2}{ab}+{b}^{\mathrm{2}} \\ $$$$\mathrm{1}.\:\left(\mathrm{50}+\mathrm{4}\right)^{\mathrm{2}} =\mathrm{2500}+\mathrm{16}+\mathrm{400}=\mathrm{2916} \\ $$$$\mathrm{2}.\:\left(\mathrm{80}+\mathrm{2}\right)^{\mathrm{2}} =\mathrm{6400}+\mathrm{4}+\mathrm{320}=\mathrm{6734} \\ $$$$\mathrm{3}.\:\left(\mathrm{100}+\mathrm{3}\right)^{\mathrm{2}} =\mathrm{10000}+\mathrm{9}+\mathrm{600}=\mathrm{10609} \\ $$$$\mathrm{4}.\left(\mathrm{700}+\mathrm{4}\right)^{\mathrm{2}} =\mathrm{490000}+\mathrm{16}+\mathrm{5600}=\mathrm{495616} \\ $$