Question Number 44809 by jasno91 last updated on 05/Oct/18
Commented by Joel578 last updated on 05/Oct/18
$$\mathrm{Just}\:\mathrm{substitute}\:{x}\:\mathrm{with}\:\mathrm{12} \\ $$$$\mathrm{9}\left(\mathrm{12}^{\mathrm{2}} \right)\:+\:\mathrm{24}\left(\mathrm{12}\right)\:+\:\mathrm{16} \\ $$