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Question-45166




Question Number 45166 by peter frank last updated on 09/Oct/18
Answered by MrW3 last updated on 10/Oct/18
N=number of students  when the students are divided into  12 groups, the last group has 5 students,  i.e. the other 11 groups have x students  with x≠5.  N=11x+5 with x≠5  similarly  N=8y+5 with y≠5  since the LCM of 11 and 8 is 88,  ⇒N=88k+5 with k∈N  i.e. the class has 93 students. and  the classroom is very large.    The question may mean something  different, but the language gives  this result.
$${N}={number}\:{of}\:{students} \\ $$$${when}\:{the}\:{students}\:{are}\:{divided}\:{into} \\ $$$$\mathrm{12}\:{groups},\:{the}\:{last}\:{group}\:{has}\:\mathrm{5}\:{students}, \\ $$$${i}.{e}.\:{the}\:{other}\:\mathrm{11}\:{groups}\:{have}\:{x}\:{students} \\ $$$${with}\:{x}\neq\mathrm{5}. \\ $$$${N}=\mathrm{11}{x}+\mathrm{5}\:{with}\:{x}\neq\mathrm{5} \\ $$$${similarly} \\ $$$${N}=\mathrm{8}{y}+\mathrm{5}\:{with}\:{y}\neq\mathrm{5} \\ $$$${since}\:{the}\:{LCM}\:{of}\:\mathrm{11}\:{and}\:\mathrm{8}\:{is}\:\mathrm{88}, \\ $$$$\Rightarrow{N}=\mathrm{88}{k}+\mathrm{5}\:{with}\:{k}\in\mathbb{N} \\ $$$${i}.{e}.\:{the}\:{class}\:{has}\:\mathrm{93}\:{students}.\:{and} \\ $$$${the}\:{classroom}\:{is}\:{very}\:{large}. \\ $$$$ \\ $$$${The}\:{question}\:{may}\:{mean}\:{something} \\ $$$${different},\:{but}\:{the}\:{language}\:{gives} \\ $$$${this}\:{result}. \\ $$
Commented by peter frank last updated on 10/Oct/18
thank you sir
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$

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