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Question-45609




Question Number 45609 by peter frank last updated on 14/Oct/18
Commented by MrW3 last updated on 14/Oct/18
(b/(sin B))=(a/(sin A))=(a/(sin (B+C)))  ⇒b=a((sin B)/(sin (B+C)))  Area=(1/2)ab sin C=((a^2 sin B sin C)/(2 sin (B+C)))    but this has nothing to do with s.
$$\frac{{b}}{\mathrm{sin}\:{B}}=\frac{{a}}{\mathrm{sin}\:{A}}=\frac{{a}}{\mathrm{sin}\:\left({B}+{C}\right)} \\ $$$$\Rightarrow{b}={a}\frac{\mathrm{sin}\:{B}}{\mathrm{sin}\:\left({B}+{C}\right)} \\ $$$${Area}=\frac{\mathrm{1}}{\mathrm{2}}{ab}\:\mathrm{sin}\:{C}=\frac{{a}^{\mathrm{2}} \mathrm{sin}\:{B}\:\mathrm{sin}\:{C}}{\mathrm{2}\:\mathrm{sin}\:\left({B}+{C}\right)} \\ $$$$ \\ $$$${but}\:{this}\:{has}\:{nothing}\:{to}\:{do}\:{with}\:{s}. \\ $$
Commented by peter frank last updated on 14/Oct/18
thanks
$$\mathrm{thanks} \\ $$
Commented by peter frank last updated on 14/Oct/18
help sir  Qn 45514
$$\mathrm{help}\:\mathrm{sir}\:\:\mathrm{Qn}\:\mathrm{45514} \\ $$

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