Question Number 45920 by byaw last updated on 18/Oct/18
Answered by math1967 last updated on 19/Oct/18
$$\left.{i}\right)\:{All}\:\mathrm{4}\:{balls}\:{are}\:{black}=\:\frac{\:^{\mathrm{8}} {c}_{\mathrm{2}} \:}{\:^{\mathrm{20}} {c}_{\mathrm{2}} }\cap\frac{\:^{\mathrm{15}} {c}_{\mathrm{2}} }{\:^{\mathrm{25}} {c}_{\mathrm{2}} }\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{14}}{\mathrm{95}}×\frac{\mathrm{7}}{\mathrm{20}}=\frac{\mathrm{49}}{\mathrm{950}}\:{ans}.\: \\ $$$$\left.{ii}\right)\:\frac{\:^{\mathrm{12}} {c}_{\mathrm{1}} ×\:^{\mathrm{8}} {c}_{\mathrm{1}} }{\:^{\mathrm{20}} {c}_{\mathrm{2}} }\:×\frac{\:^{\mathrm{15}} {c}_{\mathrm{2}} }{\:^{\mathrm{25}} {c}_{\mathrm{2}} }\:\cup\frac{\:^{\mathrm{10}} {c}_{\mathrm{1}\:} ×\:^{\mathrm{15}} {c}_{\mathrm{1}} }{\:^{\mathrm{25}} {c}_{\mathrm{2}} }×\frac{\:^{\mathrm{8}} {c}_{\mathrm{2}} }{\:^{\mathrm{20}} {c}_{\mathrm{2}} } \\ $$$$=\frac{\mathrm{12}×\mathrm{8}×\mathrm{15}×\mathrm{7}}{\mathrm{10}×\mathrm{19}×\mathrm{25}×\mathrm{12}}\:+\frac{\mathrm{10}×\mathrm{15}×\mathrm{4}×\mathrm{7}}{\mathrm{25}×\mathrm{12}×\mathrm{10}×\mathrm{19}} \\ $$$$ \\ $$