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Question-45992




Question Number 45992 by sandeepkeshari0797@gmail.com last updated on 19/Oct/18
Answered by tanmay.chaudhury50@gmail.com last updated on 19/Oct/18
2+3×1=5  2+5×2=12  3+6×3=21  8+11×4=52   i think so...
$$\mathrm{2}+\mathrm{3}×\mathrm{1}=\mathrm{5} \\ $$$$\mathrm{2}+\mathrm{5}×\mathrm{2}=\mathrm{12} \\ $$$$\mathrm{3}+\mathrm{6}×\mathrm{3}=\mathrm{21} \\ $$$$\mathrm{8}+\mathrm{11}×\mathrm{4}=\mathrm{52}\:\:\:{i}\:{think}\:{so}… \\ $$$$ \\ $$
Commented by MJS last updated on 19/Oct/18
only the first one doesn′t fit... one of a zillion  possibilities:  0+3+2=5  2+5+5=12  3+6+12=21  8+11+21=40  17+20+40=77  30+33+77=140  47+50+140=237  ...
$$\mathrm{only}\:\mathrm{the}\:\mathrm{first}\:\mathrm{one}\:\mathrm{doesn}'\mathrm{t}\:\mathrm{fit}…\:\mathrm{one}\:\mathrm{of}\:\mathrm{a}\:\mathrm{zillion} \\ $$$$\mathrm{possibilities}: \\ $$$$\mathrm{0}+\mathrm{3}+\mathrm{2}=\mathrm{5} \\ $$$$\mathrm{2}+\mathrm{5}+\mathrm{5}=\mathrm{12} \\ $$$$\mathrm{3}+\mathrm{6}+\mathrm{12}=\mathrm{21} \\ $$$$\mathrm{8}+\mathrm{11}+\mathrm{21}=\mathrm{40} \\ $$$$\mathrm{17}+\mathrm{20}+\mathrm{40}=\mathrm{77} \\ $$$$\mathrm{30}+\mathrm{33}+\mathrm{77}=\mathrm{140} \\ $$$$\mathrm{47}+\mathrm{50}+\mathrm{140}=\mathrm{237} \\ $$$$… \\ $$

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