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Question-46025




Question Number 46025 by Sanjarbek last updated on 20/Oct/18
Answered by tanmay.chaudhury50@gmail.com last updated on 20/Oct/18
ln_(sinx) cosx=4−x  (sinx)^(4−x) =cosx
$${ln}_{{sinx}} {cosx}=\mathrm{4}−{x} \\ $$$$\left({sinx}\right)^{\mathrm{4}−{x}} ={cosx} \\ $$

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