Question Number 46121 by Sanjarbek last updated on 21/Oct/18
Commented by tanmay.chaudhury50@gmail.com last updated on 21/Oct/18
$${as}\:{x}\rightarrow\infty\:\:\:{so}\:\mathrm{2}^{{x}} \rightarrow\infty \\ $$$${hence}\:\mathrm{3}^{\mathrm{2}^{{x}} } \rightarrow\infty \\ $$$${so}\:{finally} \\ $$$$\left(\mathrm{3}^{\mathrm{2}^{{x}} } −\mathrm{2}\right)\rightarrow\infty \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\mathrm{3}^{\mathrm{2}^{{x}} } −\mathrm{2}\right)=\infty \\ $$