Question-46673

Question Number 46673 by Tawa1 last updated on 30/Oct/18

Commented by Smail last updated on 30/Oct/18

α i s a c o n s t a n t y o u s h o u l d n o t r e p l a c e i t w i t h t 2^{x} .

Commented by Smail last updated on 30/Oct/18

T h e r i g h t a n s w e r i s

\underset{t \to 0}{l i m} \frac{s i n (α)}{\frac{α}{t} s i n (t)} = \frac{s i n (α)}{α}

Commented by maxmathsup by imad last updated on 30/Oct/18

y e s y o u a r e r i g h t i d o n t c a r e t o t h i s p o i n t w e h a v e

A (x) = \frac{s i n (α)}{2^{x} s i n (\frac{α}{2^{x}})} = \frac{s i n (α)}{α \frac{s i n (\frac{α}{2^{x}})}{\frac{α}{2^{x}}}} \to \frac{s i n (α)}{α} (x \to + \infty) h e r e w e s u p p o s e α \neq k π

i f α = k π A (x) = 0 \Rightarrow {l i m}_{x \to + \infty} A (x) = 0

Commented by Tawa1 last updated on 30/Oct/18

God bless you sir

Commented by maxmathsup by imad last updated on 30/Oct/18

y o u a r e w e l c o m e s i r .