Question Number 47646 by Umar last updated on 12/Nov/18
Commented by tanmay.chaudhury50@gmail.com last updated on 12/Nov/18
Commented by tanmay.chaudhury50@gmail.com last updated on 12/Nov/18
Answered by tanmay.chaudhury50@gmail.com last updated on 12/Nov/18
$${E}=\frac{\sigma}{\mathrm{2}\epsilon_{\mathrm{0}} } \\ $$$$\sigma=\frac{\mathrm{1500}×\mathrm{10}^{−\mathrm{6}} {C}}{\mathrm{300}{m}^{\mathrm{2}} }=\mathrm{5}×\mathrm{10}^{−\mathrm{6}} \\ $$$$\epsilon_{\mathrm{0}} =\mathrm{8}.\mathrm{85}×\mathrm{10}^{−\mathrm{12}} \\ $$$${E}=\frac{\mathrm{5}×\mathrm{10}^{−\mathrm{6}} }{\mathrm{8}.\mathrm{85}×\mathrm{10}^{−\mathrm{12}} } \\ $$$$=\mathrm{0}.\mathrm{56}×\mathrm{10}^{\mathrm{6}} \:\:\left({approx}\right) \\ $$$$= \\ $$
Commented by Umar last updated on 12/Nov/18
$$\mathrm{wow}!\:\: \\ $$$$\mathrm{thank}\:\mathrm{u}\:\mathrm{so}\:\mathrm{much}\:\mathrm{sir}. \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 13/Nov/18
$${most}\:{welcome}… \\ $$