Menu Close

Question-48711




Question Number 48711 by somil last updated on 27/Nov/18
Commented by mr W last updated on 27/Nov/18
A+B+C=π  A+B=π−C  ((A+B)/2)=(π/2)−(C/2)  sin (((A+B)/2))=sin ((π/2)−(C/2))=cos (C/2)
$${A}+{B}+{C}=\pi \\ $$$${A}+{B}=\pi−{C} \\ $$$$\frac{{A}+{B}}{\mathrm{2}}=\frac{\pi}{\mathrm{2}}−\frac{{C}}{\mathrm{2}} \\ $$$$\mathrm{sin}\:\left(\frac{{A}+{B}}{\mathrm{2}}\right)=\mathrm{sin}\:\left(\frac{\pi}{\mathrm{2}}−\frac{{C}}{\mathrm{2}}\right)=\mathrm{cos}\:\frac{{C}}{\mathrm{2}} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 27/Nov/18
sin(((A+B)/2))  =sin(((π−C)/2))  =sin((π/2)−(C/2))  =Cos((C/2))
$${sin}\left(\frac{{A}+{B}}{\mathrm{2}}\right) \\ $$$$={sin}\left(\frac{\pi−{C}}{\mathrm{2}}\right) \\ $$$$={sin}\left(\frac{\pi}{\mathrm{2}}−\frac{{C}}{\mathrm{2}}\right) \\ $$$$={Cos}\left(\frac{{C}}{\mathrm{2}}\right) \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *