Question Number 48845 by ggny last updated on 29/Nov/18
Commented by tanmay.chaudhury50@gmail.com last updated on 29/Nov/18
$${pls}\:{clarify}\:{what}\:{is}\:\mathrm{28},\mathrm{8}\:{means} \\ $$$${is}\:{it}\:\mathrm{288}\:{or}\:\mathrm{28}.\mathrm{8} \\ $$
Answered by tanmay.chaudhury50@gmail.com last updated on 29/Nov/18
$$\left.{a}\right)\frac{\mathrm{28}.\mathrm{8}}{\left(\mathrm{13}\frac{\mathrm{5}}{\mathrm{7}}\right)}=\frac{\mathrm{28}.\mathrm{8}×\mathrm{7}}{\mathrm{96}}=\mathrm{0}.\mathrm{3}×\mathrm{7}=\mathrm{2}.\mathrm{1} \\ $$$$\left.{b}\right)\frac{\mathrm{6}.\mathrm{6}}{\frac{\mathrm{2}}{\mathrm{3}}}=\frac{\mathrm{6}.\mathrm{6}×\mathrm{3}}{\mathrm{2}}=\mathrm{3}.\mathrm{3}×\mathrm{3}=\mathrm{9}.\mathrm{9} \\ $$$${so}\:{a}+{b}=\mathrm{2}.\mathrm{1}+\mathrm{9}.\mathrm{9}=\mathrm{12} \\ $$$$\left.{c}\right)\frac{\mathrm{1}\frac{\mathrm{11}}{\mathrm{16}}}{\mathrm{2}.\mathrm{25}}=\frac{\mathrm{27}}{\mathrm{16}×\mathrm{2}.\mathrm{25}}=\frac{\mathrm{27}}{\mathrm{36}}=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$${so}\:\frac{{a}+{b}}{{c}}=\frac{\mathrm{12}}{\frac{\mathrm{3}}{\mathrm{4}}}=\frac{\mathrm{12}×\mathrm{4}}{\mathrm{3}}=\mathrm{16} \\ $$