Question Number 49096 by peter frank last updated on 02/Dec/18
Answered by tanmay.chaudhury50@gmail.com last updated on 02/Dec/18
$$\left.{a}\right){velocity}\:{of}\:{man}\:{w}.{r}.{t}\:{ground}\:={V}_{{G}} ^{{m}} ={V}_{{G}} ^{{B}} +{V}_{{B}} ^{{m}} \\ $$$${if}\:{the}\:{was}\:{seated}\:{in}\:{chair}\:{or}\:{standing}\: \\ $$$${then}\:{velocity}\:{of}\:{man}\:{w}.{r}.{t}\:{ground}=\mathrm{56}.\mathrm{2}\:{km} \\ $$$${now}\:{imagine}\:{the}\:{man}\:{is}\:{moving}\:{with}\:{velocity} \\ $$$${x}\:\:{w}.{r}.{t}\:{BUS}\:{in}\:{the}\:{same}\:{direction}\:{of}\:{bus}\:{moving} \\ $$$${then}\: \\ $$$${V}_{{G}} ^{{m}} ={V}_{{B}} ^{{m}} +{V}_{{G}} ^{{B}} \\ $$$$\:\:\mathrm{55}.\mathrm{8}={x}+\mathrm{56}.\mathrm{2} \\ $$$${x}=−\mathrm{0}.\mathrm{4} \\ $$$$\:{x}\:{value}\:\left(−{ve}\right){sign}\:{the}\:{man}\:{is}\:{moving}\:{towards}\:{back}… \\ $$$${pls}\:{check}\:{is}\:{it}\:{correct}… \\ $$$$ \\ $$$$\: \\ $$