Question-49356

Question Number 49356 by peter frank last updated on 06/Dec/18

Commented by peter frank last updated on 07/Dec/18

am getting greatest area is 4 π a .

Answered by tanmay.chaudhury50@gmail.com last updated on 06/Dec/18

2) s o l v e x + y - 1 = 0

y^{2} = 6 x

{(1 - x)}^{2} = 6 x

1 - 2 x + x^{2} - 6 x = 0

x^{2} - 8 x + 1 = 0

x_{1} + x_{2} = - (- 8) = 8

\frac{x_{1} + x_{2}}{2} = 4

y = 1 - x

y_{1} = 1 - x_{1}

y_{2} = 1 - x_{2}

y_{1} + y_{2} = 2 - (x_{1} + x_{2}) = 2 - 8 = - 6

\frac{y_{1} + y_{2}}{2} = - 3

s o t h e m i d p o i n t s o f c h o r d s (4, - 3)