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Question-49767




Question Number 49767 by ggny last updated on 10/Dec/18
Answered by afachri last updated on 10/Dec/18
1)  ((11^(20) . (2^(−3) )^6 . 2^(24) )/(2^4  . 11^(19) ))  =  ((11^(20 ) . 2^(−18)  . 2^(24 ) )/(11^(19)  . 2^4 ))                                                     =  11^((20 − 19))  . 2^((−18 + 24 − 4))                                                    =  11 . 2^2  = 44
$$\left.\mathrm{1}\right)\:\:\frac{\mathrm{11}^{\mathrm{20}} .\:\left(\mathrm{2}^{−\mathrm{3}} \right)^{\mathrm{6}} .\:\mathrm{2}^{\mathrm{24}} }{\mathrm{2}^{\mathrm{4}} \:.\:\mathrm{11}^{\mathrm{19}} }\:\:=\:\:\frac{\mathrm{11}^{\mathrm{20}\:} .\:\mathrm{2}^{−\mathrm{18}} \:.\:\mathrm{2}^{\mathrm{24}\:} }{\mathrm{11}^{\mathrm{19}} \:.\:\mathrm{2}^{\mathrm{4}} }\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:\mathrm{11}^{\left(\mathrm{20}\:−\:\mathrm{19}\right)} \:.\:\mathrm{2}^{\left(−\mathrm{18}\:+\:\mathrm{24}\:−\:\mathrm{4}\right)} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:\mathrm{11}\:.\:\mathrm{2}^{\mathrm{2}} \:=\:\mathrm{44} \\ $$$$ \\ $$

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