Menu Close

Question-49785

Tinku Tara 0 Comments
Pin




Question Number 49785 by ggny last updated on 10/Dec/18
Answered by afachri last updated on 10/Dec/18
(1) ((11^(20) . (2^(−3) )^6 . (2^6 )^4 )/(2^(4 ) . 11^(19) )) = 11^(20−19) . 2^(−18+24−4) = 11 . 2^2 = 44 (2) ((5^(15) . (3^4 )^2 )/((3 . 5^2 )^7 )) = ((5^(15) . 3^8 )/(5^(14) . 3^7 )) = 5^(15−14) . 3^(8−7) = 5 . 3 = 15 (3) (((2^4 )^4 . 5^8 . (2^(−1) )^7 )/((2 . 5)^7 )) = ((2^(16) . 5^8 . 2^(−7) )/(2^7 . 5^7 )) = 2^(16−7−7) . 5^(8−7) = 2^2 . 5 = 20
(1)1120.(2−3)6.(26)424.1119=1120−19.2−18+24−4=11.22=44(2)515.(34)2(3.52)7=515.38514.37=515−14.38−7=5.3=15(3)(24)4.58.(2−1)7(2.5)7=216.58.2−727.57=216−7−7.58−7=22.5=20

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *